Schrödinger Eq Infinite Well Tunnelling Atom & Spin References
Spring 2026 • IIT Bombay

The Energy-Band Model
& Quantum Mechanics

Lecture 2

Understanding the microscopic world: from wave-particle duality and Schrödinger's wave equation to the one-electron atom.

AS

Instructor: Abhijeet L. Sangle

alsangle@iitb.ac.in

1D Nonrelativistic Schrödinger's Equation

Time-Dependent Form (1926)

- 2 2m 2Ψ(x,t) x2 + V(x)Ψ(x,t) = j Ψ(x,t) t
  • By separating the time and position dependent variables, assume that
Ψ(x,t) = ψ(x)ϕ(t)
Simplifying Schrödinger's equation,
-2 2m ϕ(t) d2ψ(x) dx2 + V(x)ψ(x)ϕ(t) = jψ(x) dϕ(t) dt
  • Dividing both sides by total wave function Ψ(x,t)=ψ(x)ϕ(t),
-2 2m 1ψ(x) d2ψ(x) dx2 + V(x) = j 1ϕ(t) dϕ(t) dt
  • LHS function of x only, RHS function of t only
Each side must be equal to constant
  • Solving time-dependent portion:
η = j 1ϕ(t) dϕ(t) dt , where η is a separation constant
Now, E = hν = h ω2π = η
Separation constant is equal to E (total energy of the particle)
d2ψ(x) dx2 + 2m2 (E-V(x))ψ(x) = 0

Physical Meaning of Total Wave Function

Total wave function: Ψ(x,t) = ψ(x)ϕ(t) = ψ(x)e-jωt
  • Max Born in 1926: The function |Ψ(x,t)|2 is the probability of finding the particle between x and x+dx at a given time.

Particle in an Infinite Potential Well

"I could be bounded in a nutshell, and count myself a king of infinite space..."

— William Shakespeare, Hamlet (Act 2, Scene 2)

Consider a particle trapped in a rigid box (potential well). In classical mechanics, it bounces back and forth with any energy. Quantum mechanics reveals a different reality dictated by confinement.

The Mathematical Solution

The Time-independent Schrödinger Equation (S.E.) is:

\[ \frac{d^2\psi(x)}{dx^2} + \frac{2m}{\hbar^2}(E - V(x))\psi(x) = 0 \]

Applying Boundary Conditions

  1. At \( x = 0 \), \( \psi(0) = 0 \implies A = -B \).
  2. At \( x = a \), \( \psi(a) = 0 \implies \sin(ka) = 0 \). This requires \( ka = n\pi \) (where \( n = 1, 2, 3... \)).
  3. Applying the normalization conditionThe total probability of finding the particle within the well (0 to a) must be 1. \( \int_{0}^{a} \psi\psi^* dx = 1 \).

Final Wave Function

\[ \psi_n(x) = \sqrt{\frac{2}{a}} \sin\left(\frac{n\pi x}{a}\right) \]

Interactive States Explorer

Select Energy Level

Wave Function \(\psi_n(x)\)
Probability Density \(|\psi_n(x)|^2\)

Potential Barrier & Tunnelling

"Alice laughed. 'There's no use trying,' she said. 'One can't believe impossible things.'
'I daresay you haven't had much practice,' said the Queen."

— Lewis Carroll, Through the Looking-Glass

The Setup

A potential barrier (Region II) of width '\( a \)' and height \( V_0 = 20 \text{ eV} \). Particles approach from Region I with energy \( E < V_0 \).

The Transmission Coefficient (T) is the ratio of transmitted to incident flux. For \( E \ll V_0 \):

\[ T \approx 16\left(\frac{E}{V_0}\right)\left(1 - \frac{E}{V_0}\right)e^{-2k_2a} \]

Tunnelling Simulator

3.0
2.0
Probability (T): 3.17e-6

The One-Electron Atom

We now extend our quantum mechanical toolkit from simple 1D boxes to the three-dimensional, spherically symmetric world of a one-electron atom (like Hydrogen).

The general Schrödinger equation incorporates the Laplacian operator \(\nabla^2\), taking into account the effective mass \(m_0\) (strictly the reduced mass \(\mu \approx m_0\) since \(m_p \gg m_0\)):

\( \nabla^2\psi(r,\theta,\phi) + \frac{2m_0}{\hbar^2}(E - V(r))\psi(r,\theta,\phi) = 0 \)

Deriving the Quantum Numbers

Step 1: Separation of Variables

General 3D Schrödinger Equation
\[ \nabla^2\psi + \frac{2m_0}{\hbar^2}(E - V(r))\psi = 0 \]
Assume Separable Solution

Because the Coulomb potential \(V(r)\) is spherically symmetric.

\[ \psi(r, \theta, \phi) = R(r) \cdot \Theta(\theta) \cdot \Phi(\phi) \]
Radial Eq. \(R(r)\)
Colatitude Eq. \(\Theta(\theta)\)
Azimuthal Eq. \(\Phi(\phi)\)

Step 2: Magnetic Quantum Number (\(m_l\))

Azimuthal Differential Equation
\[ \frac{d^2\Phi}{d\phi^2} + m_l^2 \Phi = 0 \implies \Phi(\phi) = A e^{j m_l \phi} \]
Physical Boundary Condition

Wavefunction must match itself exactly after a full \(360^\circ\) (\(2\pi\)) rotation around the axis:

\[ \Phi(\phi) = \Phi(\phi + 2\pi) \]
Quantization Result

\( m_l = 0, \pm1, \pm2, ... \)

(\(m_l\) must be an integer for the complex exponential equality to hold)

Step 3: Azimuthal Quantum Number (\(l\))

Colatitude Equation (\(\theta\))

Forms the mathematically rigorous Associated Legendre Differential Equation.

Physical Boundary Condition

Solution must remain finite (not blow up to infinity) at the mathematical poles (\(\theta = 0, \pi\)).

Legendre Polynomial Constraint: \( l \ge |m_l| \)
Quantization Result

\( l = 0, 1, 2, ... \)

(\(l\) is a positive integer strictly bounding the allowed magnetic states)

Step 4: Principal Quantum Number (\(n\))

Radial Equation (\(r\))

Incorporates the Coulomb potential \(V(r)\). Solved via power series expansion, forming Associated Laguerre Polynomials.

Physical Boundary Condition

To keep the electron bounded to the nucleus, the wavefunction must decay to zero as \(r \to \infty\). The infinite power series must therefore terminate.

Quantization Result
\[ E_n \propto \frac{1}{n^2} \]

\( n = 1, 2, 3, ... \)

(\(n\) must be a positive integer where \(n > l\))

\( l \) (Azimuthal / Angular)

Must be a non-negative integer (\(0, 1, 2...\)). It dictates the magnitude of orbital angular momentum. Constrained by: \( m_l \le l \).

\( n \) (Principal)

Takes positive integral values (\(1, 2, 3...\)). Primarily determines the total energy of the electron orbit.

Radial Probability Density Function \( P(r) \)

The probability of finding an electron at a specific distance \(r\) is proportional to \(\psi \psi^*\) multiplied by the differential volume of the spherical shell (\(4\pi r^2 dr\)).

Highest probability occurs exactly at \( r = a_0 \)

Spin & Pauli's Exclusion Principle

While Schrödinger’s Equation provides \(n, l,\) and \(m_l\), empirical observations of emission spectra splitting required a fourth quantum number.

Spin Quantum Number (s)

Indicates intrinsic angular momentum. It can only take values of \(+\frac{1}{2}\) or \(-\frac{1}{2}\).

"In any given system... no two electrons may occupy the same quantum state."

— Wolfgang Pauli

Reference Texts

  • 1

    Principles of Semiconductor Devices (2nd Edition)

    Sima Dimitrijev, Oxford University Press, 2012.

  • 2

    Solid State Electronic Devices (7th Edition)

    Ben G. Streetman and S. K. Banerjee, Pearson, 2016.

Practice Assessment

Lecture 2 Knowledge Check

Put your understanding of the energy-band model and quantum mechanics to the test.

Start Assessment